We have now reduced the proof of theorem 3 to that of establishing
almost surely. We will prove this by establishing
almost surely and
almost surely.
To prove 9 note that differs from
by a constant not depending on (note that we suppress the dependence of and on ). For fixed this is maximized as a function of by . The profile obtained by replacing by is concave and is maximized over all by . Since this estimate is strongly consistent on the explosion set, the profile is maximized, subject to at one of the two points . Finally, 9 is easily established by considering the two values individually.
Fix and let be the event that for all . Then and is the explosion set except for a -null event. For trajectories in with chosen large we write
We will choose and depending on . In particular let
with to be chosen later and
Each is a probability so bounded by 1. Thus
The first term in 12 is free of and after division by converges to 0 almost surely on . Also on grows exponentially when and so . From 1 we obtain
On we have . Thus, except for a fixed number of (depending only on and ) the right hand side of 13 is less than permitting a Taylor expansion of the . Hence
almost surely.
For the fourth term in 12 we have
for all . Letting a Taylor expansion of the logarithm then shows that
which converges to 0 almost surely.
It remains to deal with the second term in 12. This is the most technical part of the argument. Consider now any for which . (Remember that depends on .) There is an for which . There is then a constant not depending on or such that for all small
Since is in the convex hull of the points as runs over and since this convex hull is a regular polygon there is a constant depending only on such that there must exist an with
Finally there is a depending only on such that
Let be the set of all such that 15 holds. Note that either and the second term above is 0 or belongs to some . For in and we have
Let
Then
An argument like that at (14) shows that the sequence is asymptotically an iid sequence of uniformly distributed random variables. Using this argument we can establish
Since we can choose so that
With this choice of we can use the lemma to prove
Theorem 3 follows.